Report copyright - Computerorientiertes Problemlösen [1ex] 23. 27. …ˆ’1 +(n−1)p 2xn−2 +...+ p n >> p=[1 -8 15]; >> p1=polyder(p) p1 = 2 -8 >> p2=polyder(p1) p2 = 2 p(x) = x2 −8x+15 p0(x)
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